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6t^2-5t-24=0
a = 6; b = -5; c = -24;
Δ = b2-4ac
Δ = -52-4·6·(-24)
Δ = 601
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-5)-\sqrt{601}}{2*6}=\frac{5-\sqrt{601}}{12} $$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-5)+\sqrt{601}}{2*6}=\frac{5+\sqrt{601}}{12} $
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